Licensed Devil Posted January 23, 2004 Share Posted January 23, 2004 OK, POW#1 one knew because he could tell the other two couldn't work out what theirs were from what they could see. POW#3 didn't know what colour his was... so therefore #1+#3 either BOTH had Black, or one had Black, and one had White, because if they both had white he would have to have Black.POW#2 realises that POW#3 doesn't know, so knows that his could either be black or white because he knows that POW#1's beanie is black, so his could be black or white, so he doesn't know.POW#1 therefore realises that as neither of the other two know, his must be black. Link to comment Share on other sites More sharing options...
EKen132 Posted January 23, 2004 Share Posted January 23, 2004 Thats genius. If that's not the right answer, I'd be surprised! Link to comment Share on other sites More sharing options...
Night Hawk Posted January 24, 2004 Share Posted January 24, 2004 that is the right awnser i think Link to comment Share on other sites More sharing options...
Cougar Posted January 25, 2004 Author Share Posted January 25, 2004 We have a winner! Way to go Licensed Devil! Link to comment Share on other sites More sharing options...
Black Op Posted January 25, 2004 Share Posted January 25, 2004 Finally....... Good job Licensed Devil, despite the fact I can't really comprehend your answer. Link to comment Share on other sites More sharing options...
Cougar Posted January 25, 2004 Author Share Posted January 25, 2004 Let's see if I can show the answer in a graphical way.The POWs were lined up so that #3 could see #2 and #1, #2 could see #1 and #1 couldn't see anyone.3-> 2-> 1->There were seven possible combinations of beenies:B B B (aW B B (bB W B (cW W B (dB B W (eW B W (fB W W (g3-> 2-> 1->The only way #3 would know for certain the color of his beenie was if both #2 and #1 were wearing white (g which would mean #3 was wearing black. But this wasn't that case, so #3 didn't say anything.Since #3 stayed silent, #2 realized that #3 could see at least one black beenie. So according to #2 the possible combinations were:? B W (a? W B (b? B B (c3-> 2-> 1->#2 could see that #1 was wearing a black beenie and realized that the beenie on his own head could still be either black or white, (b or (c, so he didn't say anything either.Since #2 stayed silent, #1 realized that #2 didn't know if it was case (b or (c and in both of those cases #1 was wearing a black beenie.10 points to Licensed Devil for figuring it out. Link to comment Share on other sites More sharing options...
Licensed Devil Posted January 25, 2004 Share Posted January 25, 2004 Whoo yeah thanks Link to comment Share on other sites More sharing options...
King Tutankhamun Posted January 25, 2004 Share Posted January 25, 2004 "I can see clearly now, the rain has gone. Its gonna be... its gonna be a bright, bright sunshiny day!" *ends singing voice* Link to comment Share on other sites More sharing options...
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